(2x^2/5y^4)^-2

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Solution for (2x^2/5y^4)^-2 equation: 


D( x )

((2*x^2)/5)*y^4 = 0

((2*x^2)/5)*y^4 = 0

((2*x^2)/5)*y^4 = 0

2/5*x^2*y^4 = 0 // : 2/5*y^4

x^2 = 0

x = 0

x in (-oo:0) U (0:+oo)

(((2*x^2)/5)*y^4)^-2 = 0

25/4*x^-4*y^-8 = 0 // : 25/4*y^-8

x^-4 = 0

x należy do O

x belongs to the empty set

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